orhtej2@eviltoast.org to Programmer Humor@programming.devEnglish · 2 days agoPeak code reuseeviltoast.orgimagemessage-square41linkfedilinkarrow-up1455arrow-down15
arrow-up1450arrow-down1imagePeak code reuseeviltoast.orgorhtej2@eviltoast.org to Programmer Humor@programming.devEnglish · 2 days agomessage-square41linkfedilink
minus-squarecogman@lemmy.worldlinkfedilinkarrow-up7·2 days agoFixed boolean isOdd(int num) { if(num == 1) return true; if(num > 0) return isEven(num - 1); else return isEven(num + 1); } boolean isEven(int num) { if(num > 0) return isOdd(num - 1); else return isOdd(num + 1); }
minus-squareaffiliate@lemmy.worldlinkfedilinkarrow-up11·2 days agothe downside with this approach is that it will eventually terminate. the version in the original post has the advantage of giving me plenty of time to contemplate life’s many mysteries.
minus-squarecogman@lemmy.worldlinkfedilinkarrow-up4·2 days agoWhat can I say, I’m a performance nerd.
minus-squareRednax@lemmy.worldlinkfedilinkarrow-up3arrow-down2·2 days agoWhy the complicated if statements to check the sign? Just let the number overflow. Would be functionaly the same, and result in much prettier code.
minus-squarecogman@lemmy.worldlinkfedilinkarrow-up6·2 days agoThat’s a platform dependent change. Overflow is undefined behavior. I’d rather have my code portable so it can run on my Univac 1101.
Fixed
the downside with this approach is that it will eventually terminate. the version in the original post has the advantage of giving me plenty of time to contemplate life’s many mysteries.
What can I say, I’m a performance nerd.
isEeven(∞);
Why the complicated if statements to check the sign? Just let the number overflow. Would be functionaly the same, and result in much prettier code.
That’s a platform dependent change. Overflow is undefined behavior. I’d rather have my code portable so it can run on my Univac 1101.